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Solve the inequality. Express you answer in interval notation. -3(x + 2) > 15 or x-3< -1

User Wiktoria Prusik
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1 Answer

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SOLUTION

We are told to solve the inequality


-3\mleft(x+2\mright)>15\text{ or }x-3<-1​

This becomes


\begin{gathered} -3(x+2)>15\text{ or }x-3<-1​ \\ -3x-6>15\text{ or }x<2 \\ -3x>11\text{ or }x<2 \\ x<-(11)/(3)\text{ or }x<2 \end{gathered}

In interval notation, this becomes


(-\infty,-(11)/(3))\cup(-\infty,2)

User Iraklis Bekiaris
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