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What is the total amount of heat required to completely melt 347 grams of ice at its melting point?

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In order to calculate the amount of heat energy required to melt 347 grams of ice, we need to will apply the equation:
Q = ml, where m is the mass of substance and l is its latent heat of fusion. For ice, the latent heat of fusion is 334 joules per gram. Therefore:
Q = 347 x 334
Q = 112,558 joules of energy

Hope this helped.
User Gopal Singh Sirvi
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