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36 votes
36 votes
I need help with my math

User Jakuje
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1 Answer

27 votes
27 votes

We have a system of equations:


\begin{gathered} y=2x+4 \\ 5x+y=25 \end{gathered}

If we have to solve it by substitution, we can replace y in the second equation given that y is already cleared in the first equation. Then, replacing y, we can solve for x:


\begin{gathered} 5x+y=25 \\ 5x+(2x+4)=25 \\ 7x=25-4 \\ 7x=21 \\ x=(21)/(7) \\ x=3 \end{gathered}

With the value of x, we can solve for y as:


y=2x+4=2\cdot3+4=6+4=10

Answer: the ordered pair (x,y) that is a solution to the system is (3,10)

User Tayler
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