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What is the area of a parallelogram whose vertices are A(−1, 12) , B(13, 12) , C(2, −5) , and D(−12, −5) ? Enter your answer in the box.

User Grmartin
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2 Answers

4 votes
it should be 238 for the area

User Cengkuru Michael
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2 votes
Looking at the first two vertices, A and B, we see that the x values have a difference of (-1 - 13) units, or 14 units. This gives us the base of the parallelogram. Next, we look at the difference between the y values between B and C to find the height. In this case, they are (12 - [-5] ) units, or 17 units. The area of a parallelogram is simply base multiplied by height, which is (14 * 17), or 238 square units.
User Morgan Ng
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