Question

Find the distance CD rounded tothe nearest tenth.C = (7,-4) and D = (-8,-5)CD = [? ]HINT: Use the distance formula:d = 7 (x2 - 1)2 + (y2 - Yı)2Enter

Answer 1

Given

C = (7,-4) and D = (-8,-5)

CD = [? ]

We are finding the distance CD

`d=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}^{}`

`\begin{gathered} C=(7,-4)=(x_1,y_1) \\ D=(-8,-5)=(x_2,y_2) \\ x_1=7 \\ x_2=\text{ -8} \\ y_1\text{ = -}4 \\ y_2=\text{ -5} \\ \\ \\ \end{gathered}`

We substitute to the formula

`\begin{gathered} d=\sqrt[]{(-8_{}-7)^2+(-5-(-4)^2} \\ d=\sqrt[]{(-15)^2+(-1)^2} \\ d=\sqrt[]{225^{}+1} \\ d=\sqrt[]{226} \\ \\ d=\pm15.033296 \\ So\text{ far is distance } \\ we\text{ choose the positive d=15.0 nearest tenth} \end{gathered}`