Question

If the following cards were placed upside down what is the probability that a heart is notdrawn?P (NOT heart)= # of cards that are not hearts/# of possible outcomes

Answer 1

If the cards are placed upside down, this makes the choice made whenever a card is drawn a random probability.

There are 4 different cards in the arrangement and only 1 card with a heart on it.

Therefore, the probability of picking a heart is:

`P(\text{heart)}=(1)/(4)`

Now the probability of not picking a heart is:

`\begin{gathered} P(\text{NOT heart)=1-P(heart)} \\ \\ P(\text{NOT heart) = 1-}(1)/(4)=(3)/(4) \end{gathered}`

Therefore, the final answer is 3/4