Question

The net of a pyramid with a square base is shown below. Using the dimensions indicated, what is the surface area of the pyramid?The net indicates the pyramid has square base with an edge length of 10 and a slant height of 12.A. 340 units²B. 240 units²C. 1,200 units²D. 256 units²

Answer 1

Step-by-step explanation

To find the surface area of the pyramid, we will find the area of the square base and sum it to the areas of the triangular surfaces.

`Area\text{ of S.B =}edge\text{ }lenght^2=10^2=100units^2`

The area of one triangular surface is

`Area\text{ of T.F=}(1)/(2)* edge\text{ }length* slant\text{ }height=(1)/(2)*10*12=60cm^2`

Since the triangular prism has four triangular surfaces, therefore the sum of the area of the triangular faces is

`4* Area\text{ of T.F}=4*60=240units^2`

Therefore, the surface area of the triangular prism becomes

`\begin{gathered} S.A=4* Area\text{ of T.F}+Area\text{ of S.B} \\ =240+100=340units^2 \end{gathered}`

Answer: Option A