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A 1.00 kg block of ice at 0 °c is added to a picnic cooler. how much heat will the ice remove as its melts to water at 0 °c?

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334000J or 334kJ The heat of fusion for ice is 334 joules per gram. A kilogram is 1000 grams. Calculation is straightforward: 334J*g^-1 * 1000g = 334000J = 334kJ
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