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The length of a rectangle is 5ft longer than twice the width. If the perimeter is 100ft, find the length and width of the rectangle.

User Andreas Ley
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1 Answer

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First, lets draw our rectangle, knowing that the length is 5ft longer than twice the width. Calling X the width, we have:

The question said that the perimeter is 100ft, wich gives us the followed expression:


x\text{ + x + (2x+5) + (2x+5) = 100 }\Rightarrow\text{ 6x + 10 = 100 }\Rightarrow\text{ 6x=100-10 }

Continuing ours calculations:


6x=90\text{ }\Rightarrow\text{ x=}(90)/(6)\text{ }\Rightarrow\text{ x=15}

So, our width is 15 ft, wich means that our length 35 ft.

The length of a rectangle is 5ft longer than twice the width. If the perimeter is-example-1
User MuneebShabbir
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