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18 votes
18 votes
What are the solutions of the equation (−25)2=36?

User RredCat
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1 Answer

20 votes
20 votes

Given the following question:


(x-25)^2=36

To find the answer we are going to have to use inverse of operations to isolate the variable.


\begin{gathered} (x-25)^2=36 \\ (x-25)^2=36=x-25=\sqrt[]{36} \\ x-25=\sqrt[]{36} \\ -25+25=0 \\ \sqrt[]{36}=6=6*6 \\ 6+26=31 \\ x=31 \\ x-25=-\sqrt[]{36} \\ -\sqrt[]{36}=6i \\ x-25=6i \\ -25+25=0 \\ 6i+25=19 \\ x=19 \\ x=31 \end{gathered}

Your two solutions are "x = 19, and x = 31."

User Robin Newhouse
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