Question

How many hydrogen atoms are in 2.80 mol of ammonium sulfide?

Answer 1

You can see each (NH4)2S has
2 N atoms
8 H atoms
1 S atom

So moles H atoms = 8 x moles (NH4)2S
= 52.0 moles H

1 mole anything = 6.022x10^23 units of that anything

So number H atoms = moles H atoms x 6.022x10^23 atoms/mol
= 52.0 x 6.022x10^23 atoms/mol
= 3.13x10^25 atoms of H

Answer 2

Answer : The number of hydrogen atoms are,
`134.89* 10^(23)`

Explanation : Given,

Moles of hydrogen atoms = 2.80 mole

As we know that, the formula of ammonium sulfide is,
`(NH_4)_2S`. In ammonium sulfide, there are 2 atoms of nitrogen, 8 atoms of hydrogen and 1 atom of sulfur.

Now we have to calculate the number of hydrogen atoms.

As, 1 mole of
`(NH_4)_2S` contains
`8* 6.022* 10^(23)` number of hydrogen atoms.

So, 2.80 mole of
`(NH_4)_2S` contains
`2.80* 8* * 6.022* 10^(23)=134.89* 10^(23)` number of hydrogen atoms.

Therefore, the number of hydrogen atoms are,
`134.89* 10^(23)`