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12 votes
12 votes
if a dealer buys a car from the manufacturer for $21,050 and then sells it for $30,038, what is his markup? the markup is ____'% (type an integer or decimal rounded to the nearest tenth as needed)

User Bemwa Malak
by
2.9k points

1 Answer

19 votes
19 votes

Given:

a.) A dealer buys a car from the manufacturer for $21,050.

b.) He sells it for $30,038.

Let's now determine his markup,

We get,


\text{ Mark up (\%) = }\frac{\text{ \$30,038 - \$21,050}}{\text{ \$21,050}}\text{ x 100}
=\text{ }\frac{\text{ \$8,988}}{\text{ \$21,050}}\text{ x 100}
=\text{ 0.42698337 x 100}
\text{ }=\text{ 42.698337 \%}
\text{ Mark up }\approx\text{ 42.70\%}

Therefore, the mark up is 42.70%

User Plutoberth
by
3.1k points
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