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Solve triangle QRS with the given parts. q = 9.10, r = 18.2, Q = 30.0°

Solve triangle QRS with the given parts. q = 9.10, r = 18.2, Q = 30.0°-example-1
User Slaven Rezic
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1 Answer

15 votes
15 votes

Given:

q = 9.10, r = 18.2, Q = 30 degrees

Required: Solve triangle QRS

Step-by-step explanation:

By using the Sine rule,


(\sin Q)/(q)=(\sin R)/(r)=(\sin S)/(s)

Plug the given values.


(\sin30\degree)/(9.10)=(\sin R)/(18.2)=(\sin S)/(s)

Consider


(\sin30\degree)/(9.10)=(\sin R)/(18.2)

Solve for R.


\begin{gathered} (0.5)/(9.10)=(\sin R)/(18.2) \\ \sin R=(0.5*18.2)/(9.10) \\ =1 \\ \implies R=90\degree \end{gathered}

Now, use the fact that the sum of the interiorn angles od a r

User Stefano Fedele
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