488,308 views
12 votes
12 votes
Suppose an object starts from rest and achieves an operating speed of 33,500 rev/min. If it requires 1.6 s for the tool to reach operating speed and it is held at that speed for 50.0 s, how many rotations has the bit made? Suppose it requires another 10.0 s for the tool to return to rest. (Express your answer to two significant figures.)1. How many rotations does the tool complete from rest to finish?

User MohanaRao SV
by
2.6k points

1 Answer

11 votes
11 votes

From the information given, the object starts from rest. This means that

initial angular velocity, wo = 0

It achieves an angular speed of 33,500 rev/min. This means that

final angular velocity, wf = 33,500 rev/min

We would convert 33,500 rev/min to rev/s by dividing by 60. It becomes

558.33 rev/s

time required = 1.6

We would calculate the angular displacement, θ during this period this period by applying the formula,

θ = 1/2(wo + wf)t

θ = 1/2(0 + 558.33)1.6

θ = 446.664 rev

The object continued at this speed for 50s. This means that the angular acceleration is zero since the speed was constant. During this period,

wo = 558.33 rev/s

a = 0

t = 50

We would find the number of revolutions by applying the formula,

θ = wot + 1/2at^2

θ = 558.33 * 50 + 1/2 x 0 x 50^2

θ = 27916.5 rev

Total number of revolutions at this point is

446.664 + 27916.5 = 28363.16 revs

For the final part,

It returns to rest after 10 s. Thus,

t = 10

wf = 0

wo = 558.33

We would find the number of revolutions in this part by applying the formula

θ = 1/2(wo + wf)t

θ = 1/2(558.33 + 0)10

θ = 2791.65 rev

Total revolutions completed is

28363.164 + 2791.65 = 31154.81 revolutions

User Sbeliakov
by
2.7k points