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The distance between the points 5,1 and 5,-6 is the square root of length?

User Sumintra
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\bf \textit{distance between 2 points}\\ \quad \\ \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) &({{ 5}}\quad ,&{{ 1}})\quad % (c,d) &({{ 5}}\quad ,&{{ -6}}) \end{array}\qquad % distance value d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2} \\\\\\ d=√((5-5)^2+(-6-1)^2)\implies d=√(0^2+(-5)^2)\implies d=√(25)
User Ignacioricci
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