Each die has 6 possible outputs, so rolling two dice we have a total of 6 * 6 = 36 possible outputs.
From these 36 outputs, the outputs that have the larger of the two rolls equal to 6 are:
(1, 6), (2, 6), (3, 6), (4, 6), (5, 6),
(6, 1), (6, 2), (6, 3), (6, 4), (6, 5),
(6, 6).
We have a total of 11 outputs where the larger of the two rolls is equal to 6. So the probability of having any of these outputs is:
![\begin{gathered} \text{Number of possible outputs: }N\mleft(total\mright)=36 \\ \text{Number of desired outputs: }N\mleft(desired\mright)=11 \\ \text{Probability of having a desired output:} \\ P=\frac{N\mleft(\text{desired}\mright)}{N\mleft(\text{total}\mright)}=(11)/(36) \end{gathered}]()
So the probability that the larger of the two rolls was equal to six is 11/36.