Question

In circle J with mZHJK = 112 and HJ = 6 units find area of sector HJK. Round to the nearest hundredth.

Answer 1

The area of the sector is 35.17 sq. units

Step-by-step explanation:

Given that

HJ = 6 units. This is the radius, r

And area of sector is given as:

`\frac{Central\text{ Angle}}{360}(Area)`

Where

`\text{Area}=\pi r^2`

Using these, we have:

`(112)/(360)(6^2\pi)`

Evaluating, we have:

`\begin{gathered} 11.2\pi \\ =11.2*3.14 \\ =35.168 \\ \approx35.17 \end{gathered}`