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Graph a line trough the given point with the given slope. Point:(-3, 6)slope4/-5

User Shanda
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1 Answer

17 votes
17 votes

Step-by-step explanation:

We can find the equation of a line using the following:


y-y_1=m(x-x_1)

Where m is the slope and (x1, y1) are the coordinates of a point.

Now, we can replace (x1, y1) by (-3, 6) and m by 4/(-5) to get:


\begin{gathered} y-6=(4)/(-5)(x-(-3)) \\ y-6=(4)/(-5)(x+3) \\ y-6+6=(4)/(-5)(x+3)+6 \\ y=(4)/(-5)(x+3)+6 \end{gathered}

Now, we can replace the value of x, to find another point in the graph.

So if x = 2 then:


\begin{gathered} y=(4)/(-5)(2+3)+6 \\ y=(4)/(-5)(5)+6 \\ y=-4+6 \\ y=2 \end{gathered}

Answer:

Therefore, the lines pass through the points (-3, 6) and (2, 2) and the graph of the line is:

Graph a line trough the given point with the given slope. Point:(-3, 6)slope4/-5-example-1
User Djneely
by
2.5k points
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