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In the circle below, if arc AB = 97 ° and arc CD = 29 °, find the measure of < BPA.

In the circle below, if arc AB = 97 ° and arc CD = 29 °, find the measure of < BPA-example-1
User Livia
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1 Answer

12 votes
12 votes

To solve that question we will use the fact that


(AB-CD)/(2)=\angle BPA

Then, using that formula we can find the angle we want, we know that

AB = 97°

CD = 29°

Then


\begin{gathered} \begin{equation*} (AB-CD)/(2)=\angle BPA \end{equation*} \\ \\ \angle BPA=(97-29)/(2) \\ \\ \operatorname{\angle}BPA=(68)/(2) \\ \\ \operatorname{\angle}BPA=34° \end{gathered}

The angle is 34°, and the correct answer is the letter B.

User MuttonUp
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