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From a bank of 13 movies, 7 movies to be played in a specific order are chosen for a movie marathon. In how many different ways can the movies for the movie marathon be chosen?

User Hgazibara
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1 Answer

23 votes
23 votes

Answer:

1716

Step-by-step explanation:

Given a bank of 13 movies, and we're told that 7 movies to be played in a specific order are chosen for a movie marathon, we'll use the below combination formula to determine how many different ways can the movies for the movie marathon be chosen;


\text{nCr}=(n!)/(r!(n-r)!)

where n = 13 and r = 7

Let's go ahead and substitute the above values into the formula and evaluate;


\text{nCr}=(13!)/(7!(13-7)!)=(13!)/(7!6!)=(6227020800)/(3628800)=1716

User Menezes Sousa
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