Question

Hello, I need question 4 balanced and solved! Thank you!

Answer 1

Answer :16.58 grams of CBr4

Step-by-step explanation

(i) The balanced equation will be as follows:

`2Br_2(aq)+C\text{ }(s)\Rightarrow\text{ CBr}_4(s)\text{ }`

(ii) Determine Moles of Bromine

• Molecular mass Bromine =79,904 g/mol

,

• Mass of Bromine = 8 g

`\begin{gathered} Moles\text{ = Mass/ molecular mass } \\ \text{ = 8g /79.904g.mol}^(-1) \\ \text{ = 0.1 moles of bromine } \end{gathered}`

(iii) Determine moles of Carbon tetrabromide :

By stoichiometry, we can determine that :

• 2 moles bromine produces 1 mole CBr4

,

• 0.1 mole bromine will produce X moles CBr4

Therefore , moles of CBr4 = (0.1 mole Br * 1 mole CBr4 )/2 moles Br

= 0.05 moles

(iv) Calculate mass of CBr4

• moles of CBr4 = 0.05moles

• Molecular mass CBr4 =331,63 g/mol

Therefore , Mass of CBr4 is

`\begin{gathered} Mass\text{ = moles * molecular mass } \\ \text{ = 0.05 mol* 331.63g/mol} \\ \text{ =16.58 grams } \end{gathered}`

This means that 16.58 grams of CBr4 will be produced from 8 grams of bromine.