If WY+XZ = 28, what is the length of PZ in parallelogram WXYZ?

The Worst Shady asked Jun 5, 2023

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The Worst Shady asked Jun 5, 2023

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14 votes

Given data:

The expression for the sum of diagonals is WY+XZ = 28.

The given length is WP=8.

In parallelogram diagonals always bisects each other.

$\begin{gathered} WY=2(WP) \\ =2(8) \\ =16 \end{gathered}$

Substitute 16 for WP in the given expression.

$\begin{gathered} 16+XZ=28 \\ XZ=12 \\ 2(PZ)=12 \\ PZ=6 \end{gathered}$

Thus, PZ length is 6 units.

Gomons answered Jun 12, 2023

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