Question

Which graph shows rotational symmetry?

On a coordinate plane, a sine curve goes through one cycle and is represented by f (x). The curve has a minimum of (2, negative 2), a maximum of (negative 2, 2), and goes through (0, 0).
On a coordinate plane, the function g(x) has two connected curves. The first curve goes through point (negative 3, negative 2) to (0, 0). The second curve goes from (0, 0) through (2, 3).
On a coordinate plane, the function h (x) is a v shape that opens down. The function has a vertex at (0,0) and goes through (negative 4, negative 4) and (4, negative 4).
On a coordinate plane, a parabola opens up. It goes through (negative 2, 4), has a vertex at (0, 0), and goes through (2, 4).

Answer 1

B on edge

Explanation:

Answer 2

The graph which is showing rotational symmetry is On a coordinate plane, a sine curve goes through one cycle and is represented by f (x). The curve has a minimum of (2, negative 2), a maximum of (negative 2, 2), and goes through (0, 0).

The correct answer is option A.

The sine curve represented by f(x) exhibits rotational symmetry, a property where the graph remains unchanged after a rotation. In one cycle, the sine curve reaches its maximum at (−2, 2), crosses the x-axis at (0, 0), and reaches its minimum at (2, −2).

These key points are symmetric about the origin. When the curve is rotated by 180 degrees (half of a complete rotation), the points interchange positions but maintain the same relative arrangement, confirming rotational symmetry. This symmetry is a result of the sine function's periodic nature.

In summary, the sine curve demonstrates rotational symmetry because its shape remains unchanged after a rotation. Key points, such as the maximum, minimum, and zero-crossings, maintain a symmetrical arrangement.

Therefore, option A is correct, as the sine curve indeed possesses rotational symmetry.