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How much work (in J) is involved in a chemical reaction if the volume decreases from 5.00 to 1.48 L against a constant pressure of 0.819 atm?
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How much work (in J) is involved in a chemical reaction if the volume decreases from 5.00 to 1.48 L against a constant pressure of 0.819 atm?

User ZephyrPLUSPLUS
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1 Answer

1 vote
Given:
ΔV = 5 - 1.48 L = 3.52 L = 0.00352 m³, th chane in volume
p = 0.818 atm = 0.819*101325 Pa = 82985.2 Pa

By definition, the work done is

W = \int pdV = (82985.2 \, (N)/(m^(2)) )*(0.00352 \, m^(3)) = 292.1 \, J

Answer: 292.1 J
User GuiFalourd
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