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A person runs up 37 stairs of height 0.24 m. The person weighs 701.31 N. Howmuch energy does it take for the person to reach the top of the stairs?

User Crodjer
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1 Answer

13 votes
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Given data:

* The weight of the person is 701.31 N.

* The height of the each stair is 0.24 m.

* The number of stairs given is 37.

Solution:

The energy required to reach the top of stairs is,


U=\text{mgH}

where mg is the weight of the person, and H is the total height of 37 stairs,

Substituting the known values,


\begin{gathered} U=701.31*(37*0.24) \\ U=6227.63\text{ J} \\ U=6.23*10^3\text{ J} \\ U=6.23\text{ kJ} \end{gathered}

Thus, the energy required to reach the maximum height of the 37 stairs is 6.23 kJ.

User Ven
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