Question

The standard form of the equation of a circle with center (h, k) and radius r is __________________.

Answer 1

The center is at (4, -6), and the length of the radius is 5.

Explanation:

(x − 4)2 + (y + 6)2 = 25

(x − 4)2 + (y − (-6))2 = 52

When I compare my equation with the standard form, (x − h)2 + (y − k)2 = r2, I get h = 4, k = -6, and r = 5. The center is at (4, -6), and the length of the radius is 5.

plato answer

Answer 2

`\bf \textit{equation of a circle}\\\\ (x-{{ h}})^2+(y-{{ k}})^2={{ r}}^2 \qquad \begin{array}{lllll} center\ (&{{ h}},&{{ k}})\qquad radius=&{{ r}} \end{array}`