Question

What is 6 to the negative 1 times (-2) to the third power times (-4) to the negative 2

Answer 1

The answer is:
`(1)/(12)` .
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Step-by-step explanation:
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We have: " 6⁻¹ * (-2)³ * (-4)⁻² = ? " ;
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Note: "6⁻¹ =
`(1)/(6^1)` =
`(1)/(6)` " .

Note the following property of exponents:
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a⁻ˣ =
`(1)/(x^a)` ; {x ≠ 0}.
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Note: (-2)³ = (-2)*(-2)*(-2) = 4*(-2) = -8 .
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Note: (-4)⁻² =
`(1)/((-4)^2)` ;

=
`(1)/((-4)*(-4))` ;

=
`(1)/(16)` ;
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So; we have:
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6⁻¹ * (-2)³ * (-4)⁻² ;

=
`((1*8*1))/((6*16))` ;

→ Cancel out the "8" in the "numerator" (to a "1") ; and the "16" in the number (and change to a "2"); since: {"16÷8 = 2" ; and since: "{8÷8=1"} ;

→and we have:


`((1*1*1))/((6*2))` ;

=
`(1)/(12)` .
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→ The answer is:
`(1)/(12)` .
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