Question

I am having a bit of a hard time answering this, I was going to put the effect would an an increase area due to the increase in perimeter.

Answer 1

Given:

The dimensions of rectangle are doubled.

Required:

What is the effect on the perimeter and area of the rectangle?

Step-by-step explanation:

We know the perimeter and the area of rectangle is:

`\begin{gathered} Perimeter(P)=2(length(l)+width(w)) \\ Area(A)=length* width \end{gathered}`

if dimensions are doubled then

`\begin{gathered} let\text{ }l_1=2l\text{ and }w_1=2w \\ P_1=2(l_1+w_1) \\ =2(2l+2w) \\ =2[2(l+w)] \\ =2P \end{gathered}`

and

`\begin{gathered} A_1=l_1* w_1 \\ =2l*2w \\ =4(l* w) \\ =4A \end{gathered}`

Answer:

`\begin{gathered} \text{ After dimensions get doubled perimeter get 2 multiple and area gets} \\ \text{ 4 times.} \end{gathered}`