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14 votes
14 votes
5a + 3- a = 4ainfiniteonenone

User Janwo
by
3.0k points

1 Answer

23 votes
23 votes

Step-by-step explanation:

First add similar terms:


\begin{gathered} 5a-a+3=4a \\ 4a+3=4a \end{gathered}

Substract 3 from both sides:


\begin{gathered} 4a+3-3=4a-3 \\ 4a=4a-3 \end{gathered}

Substract 4a from both sides:


\begin{gathered} 4a-4a=4a-4a-3 \\ 0=-3 \end{gathered}

The solution is contradictory, therefore this equation has no solution

Answer:

The answer is none

User Kleinfreund
by
3.0k points
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