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Ken and roberta each sold fifty tickets for the school play. the cost of a student ticket was three fourths the cost of an adult ticket. roberta sold ten more student tickets that adult tickets and collected a total of $212.50.

a. how many tickets did roberta sell?
b. what was the cost of a student ticket?
c. if ken collected $200 in all, how many student tickets did he sell?

User ISmita
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2 Answers

3 votes

Final answer:

Roberta sold 30 tickets in total, with 10 adult tickets and 20 student tickets. The cost of a student ticket was $3. Ken collected $200 in total and sold 20 student tickets.

Step-by-step explanation:

To solve this problem, we can set up two equations based on the given information. Let's use variables to represent the unknown quantities.

Let's say the cost of an adult ticket is A dollars. Then the cost of a student ticket would be 3/4 of A dollars, or (3/4)A dollars.

Based on the information given, we can set up the following equations:

Robera sold 10 more student tickets than adult tickets, so let's say she sold X adult tickets and X + 10 student tickets.

The total collected by Roberta was $212.50, so we have the equation:

(A * X) + ((3/4)A * (X + 10)) = $212.50

Ken sold 50 tickets in total, so he sold 50 - (X + 10) student tickets. The total collected by Ken was $200, so we have the equation:

((3/4)A * (50 - (X + 10))) + (A * X) = $200

Now we can solve these equations to find the values of X and A.

Plugging in A = 4, we get X = 10. Therefore, Roberta sold 10 adult tickets and 20 student tickets. The cost of a student ticket was (3/4) * 4 = $3.

In conclusion, Roberta sold 30 tickets in total, with 10 adult tickets and 20 student tickets. The cost of a student ticket was $3. Ken collected $200 in total and sold 20 student tickets.

User Alexander Matusiak
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6.9k points
5 votes
There were 40 students tickets sold
User NineCattoRules
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8.2k points