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20 votes
20 votes
solve for the varaiables shown in the steps simplifiying the expression below: 2^5 × 8^4/16 = 2^5 × (2^a)^4/2^4 = 2^5 × 2^b/2^4 = 2^c

solve for the varaiables shown in the steps simplifiying the expression below: 2^5 × 8^4/16 = 2^5 × (2^a-example-1
User Pedro Pimont
by
2.8k points

1 Answer

18 votes
18 votes

given the expresions

Solving a


(2^5*8^4)/(16)=(2^5*(2^a)^4)/(2^4)
(8^4)/(16)=((2^a)^4)/(2^4)
(8^4)/(16)=((2^a)^4)/(16)
8^4=(2^a)^4
8=(2^a)
a=3

Solving b


(2^5\cdot8^4)/(16)=(2^5*2^b)/(2^4)
(2^5\cdot8^4)/(16)=(2^5*2^b)/(16)
2^5\cdot8^4=2^5*2^b
8^4=2^b
((2)^3)^4=2^b
2^(12)=2^b
b=12

solving C


\:(2^5\cdot8^4)/(16)=2^c
\:(2^5\cdot2^(12))/(2^4)=2^c
\:(2^((5+12)))/(2^4)=2^c
\:(2^((17)))/(2^4)=2^c
\:2^((17-4))=2^c
\:2^((13))=2^c
C=13

then

A=3

B=12

C=13

User Meklarian
by
3.2k points
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