Question

-Exponential and Logarithmic Functions- Graph and state the equation of any asymptotes

Answer 1

Recall that:

`\begin{gathered} a^(-n)=(1)/(a^n), \\ n>0. \end{gathered}`

Notice that as

`\begin{gathered} x\rightarrow-\infty, \\ 2^(x+1)\rightarrow0, \end{gathered}`

then

`f(x)\rightarrow-2.`

Therefore, the graph has a horizontal asymptote with equation y=-2.

Answer:

Graph:

Asymptote:

`y=-2.`