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if it take off a lost city of an airplane on a run away is 300 km/hr with an acceleration of 2 m/s^2 what is a takeoff time of the airplane

if it take off a lost city of an airplane on a run away is 300 km/hr with an acceleration-example-1
User Maksym Petrenko
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1 Answer

14 votes
14 votes

Given:

The take-off velocity of the plane, v=300 km/hr

The acceleration of the plane, a=2 m/s²

To find:

The takeoff time of the airplane.

Step-by-step explanation:

The initial velocity of the plane, u=0 m/s

The takeoff velocity of the plane in m/s is,


\begin{gathered} v=300*(1000)/(3600) \\ =83.33\text{ m/s} \end{gathered}

From the equation of motion,


v=u+at

Where t is the takeoff time of the plane.

On substituting the known values,


\begin{gathered} 83.33=0+2t \\ \Rightarrow t=(83.33)/(2) \\ =41.7\text{ s} \end{gathered}

Final answer:

The takeoff time of the plane is 41.7 s

User TartanLlama
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