Question

If it takes 963 calories to increase the temperature of 100 grams of a substance by 90.0 degrees Celsius then how many calories does it take to raise the temperature of 300 grams of the same substance by 90.0 degrees Celsius? A)28890 B)578 C)413

Answer 1

Given:

The mass of the substance is m = 100 g

The temperature change is

`\Delta T=90^(\circ)\text{ C}`

The heat provided to the substance is Q = 963 cal

To find the heat required by the same substance to raise the temperature of the substance by 90 degrees Celsius of mass m' = 300 g

Step-by-step explanation:

First we need to find the specific heat of the substance by the formula

`Q=mc\Delta T`

Substituting the values, the specific heat of the substance will be

`\begin{gathered} c=(Q)/(m\Delta T) \\ =0.107cal/g^(\circ)C \end{gathered}`

The heat required by the same substance of mass m' to raise the temperature by 90 degrees Celsius will be

`\begin{gathered} Q^(\prime)\text{ =m'c}\Delta T^(\prime) \\ =300*0.107\text{ }*90 \\ =2889\text{ calories} \end{gathered}`

Final Answer: The heat required by the substance of mass 300 g to raise the temperature by 90 degrees Celsius is 2889 calories.