Answer: Yes it's a factor
Step-by-step explanation:
Apply the sum of cubes factoring rule to get
a^3+b^3 = (a+b)(a^2-ab+b^2)
x^3+2^3 = (x+2)(x^2-x*2+2^2)
x^3+8 = (x+2)(x^2-2x+4)
The expression x^3+8 fully factors to (x+2)(x^2-2x+4), and (x+2) is one of those factors.