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5 votes
What are potential roots of p(x) = x4 + 22x2 – 16x – 12

User Yexo
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2 Answers

4 votes
Simplify 22\times 222×2 to 4444
{x}^{4}+44-16x-12x​4​​+44−16x−12Collect like terms
{x}^{4}+(44-12)-16xx​4​​+(44−12)−16x Simplify{x}^{4}+32-16xx​4​​+32−16x
User Emonik
by
6.3k points
3 votes

Answer:

±1, ±2, ±3, ±4, ±6 and ±12

Explanation:

The potential roots are obtained as following:

potential roots = factors of the constant term / factors of leading coefficient

The constant term is -12, its factors are ±1, ±2, ±3, ±4, ±6 and ±12

The leading coefficient is 1, its factors are ±1

Therefore the potential roots are ±1, ±2, ±3, ±4, ±6 and ±12

User Sherrel
by
6.9k points
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