Let the number of adult tickets sold be represented by a
Let the number o student tickets sold be represented by s
On the first day
12 adult tickets were sold and 2 students tickets were sold
=> 12a + 2s
The amount equals $134
12a + 2s = 134 ........ Equation 1
On the second day
13 adult tickets were sold and 8 students tickets which equal $ 186
13a + 8s = 186 ------ Equation 2
Equations 1 and 2 can be solved simultaneously
Using the Elimination Method
Equation 1 can be multiplied by 4 so that the variable s will be eliminated
=> 48a + 8s = 536 ---- Equation 3
Equation 2 can now be subtracted from equation 3
48a - 13a = 536 - 186
35a = 350
Divide both sides by 35
a =350/ 35
a = 10
To get s, substitute a = 10 into Equation 1
12a + 2s = 134
12 x 10 + 2s = 134
120 + 2s = 134
2s = 134 - 120
2s = 14
Divide both sides by 2
s = 7
The price of an adult ticket is $10
The price of a student ticket is $7