Question

solve the system algebraically using the substitution methodA. (5, 3)B. (21, -13)C. (3, 5)D. (-13, 21)

Answer 1

Given the following System of equation:

`\begin{cases}y=8-x \\ 4x-3y=-3\end{cases}`

You can solve it using the Substitution method. The steps are shown below:

1. You can substitute the first equation into the second equation:

`\begin{gathered} 4x-3y=-3 \\ 4x-3(8-x)=-3 \end{gathered}`

2. Now you have to solve for the variable "x":

`\begin{gathered} 4x-24+3x=-3 \\ 7x=-3+24 \\ \\ x=(21)/(7) \\ \\ x=3 \end{gathered}`

3. Finally, substitute the value of "x" into the first equation and evaluate, in order to find the value of "y". Then:

`\begin{gathered} y=8-x \\ y=8-(3) \\ y=5 \end{gathered}`

You can write the solution in this form:

`(3,5)`

The answer is: Option C.