Question

A star with a mass of 3.72 x 1030 kilograms and a radius of 8.67 x 108 meters rotates on its axis once every 32 days. A star is a solid sphere, which has a k value of 2/5. What is the angular momentum of the star? Include units in your answer. Answer must be in 3 significant digits.

Answer 1

Given:

Mass of star, m = 3.72 x 10³⁰ kg

Radius, R = 8.67 x 10⁸ meters

Number of days, T = 32 days

k = 2/5

Let's find the angular momentum of the star.

To find the angular momentum of the star, apply the formula:

`L=kmR^2*(2\pi)/(T)`

Where:

T is the time in seconds = 60 * 60 *24 * 32 days =2764800 seconds

Thus, we have:

`\begin{gathered} L=((2)/(5)*3.72*10^(30))*(8.67*10^8)^2*(2\pi)/(2764800)^{} \\ \\ L=2.54*10^(42)kg/m^2\text{ /sec} \end{gathered}`

ANSWER:

`2.54*10^(42)kg/m^2\text{ /sec}`