Question

If a single electron has a charge of Q(e)=1.6 X 10^-19 C. Roughly how many electrons are accumulated in 0.00016 C.

Answer 1

Given data:

* The value of the charge given is,

`q=0.00016\text{ C}`

Solution:

Let n be the number of electrons in the given charge.

The net charge in terms of the number of electrons is,

`q=nQ(e)`

where Q(e) is the fundamental value of the charge,

Substituting the known values,

`\begin{gathered} 0.00016=n*1.6*10^(-19) \\ n=(0.00016)/(1.6*10^(-19)) \\ n=(1.6*10^(-4))/(1.6*10^(-19)) \\ n=1*10^(-4+19) \\ n=10^(15)\text{ } \end{gathered}`

Thus, the number of electrons in the given charge is 10^(15).