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can you please help me answer part A and B and C of question number 4 please answer clear and in detail it would be appreciated ASAP thank you very much

can you please help me answer part A and B and C of question number 4 please answer-example-1
can you please help me answer part A and B and C of question number 4 please answer-example-1
can you please help me answer part A and B and C of question number 4 please answer-example-2
User Jeff Roe
by
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1 Answer

18 votes
18 votes

SOLUTION

Given the pyramid with a square base in the image, the following are the solution steps wo find the surface area.

Step 1: Describe the formula of the surface area of the pyramid

The pyramid consists of a square base and 4 triangles, therefore the surface area of the pyramid will be the area of the square base added to the areas of the 4 triangles.

Step 2: To get the surface area of the pyramid, we calculate the area of the square base


\begin{gathered} \text{For the square base} \\ \text{Area}=s^2,s=25\text{ f}eet \\ \text{Area}=25^2=625feet^2 \end{gathered}

Step 3: We calculate the area of the 4 triangles


\begin{gathered} \text{Area}_{\text{triangle}}=(1)/(2)bh,\text{ b=25}feet,h=32 \\ \text{Area}_{\text{triangle}}=(1)/(2)*25*32 \\ \text{Area}_{\text{triangle}}=25*16=400feet^2 \\ \text{Area of 4 triangles will be 4}*\text{Area}_{\text{triangle}} \\ \text{Area}_{\text{all traingles}}=4*400 \\ \text{Area}_{\text{all traingles}}=1600feet^2 \end{gathered}

Step 4: Calculate the surface area by following the instruction in Step 1:


1600+625=2225feet^2

Hence, the surface area of the pyramid equals 2225 square feet.

Question b: Surface area of the metal soup can

The metal soup can has the shape of a cylinder, therefore the surface area will be:


\begin{gathered} SA=2\pi r^2+2\pi r^{}h,r=5,h=20\operatorname{cm} \\ SA=(2*\pi*5*5)+(2*\pi*5*20) \\ SA=157.0796327+628.3185307 \\ SA=785.3981634 \\ SA\approx785.39816\operatorname{cm} \end{gathered}

Hence, the surface area of the metal soup can equals 785.39816 square cm.

Question c: Surface area of the ice cream cone with an open top

It can be seen from the image that the height is missing from the cone.

Surafce area of a cone with an open top means we exclude the area of the circular surface:


\begin{gathered} SA=\pi rl,l=16.6\operatorname{cm},r=(9.4)/(2)=4.7\operatorname{cm} \\ SA=\pi*4.7*16.6 \\ SA=245.1070588 \\ SA\approx245.107\operatorname{cm} \end{gathered}

Hence, the surface area of the ice cream cone can equals 245.107 square cm.

User ChrisBarthol
by
3.0k points
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