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30 cars are in a race. In how many different ways can cars finish in the top 3 positions?

User TheCyberXP
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1 Answer

19 votes
19 votes

Given there are 30 cars in a race.

To find in how many ways can cars finish in the top 3 positions.

To find permutations:


\begin{gathered} ^(30)P_3=(30!)/((30-3)!) \\ =24360 \end{gathered}

Therefore, there are 24360 ways in which cars can finish in the top 3 positions.

User NTP
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