Question

What is the relative intensity of a sound wave with an intensity of 0.00458 W/m²?9.66 dB-143 dB96.6 dB-14.3 dB

Answer 1

Given

The intensity is

`I_=0.00458\text{ W/m}^2`

To find

The relative intensity

Step-by-step explanation

The relative intensity is given by

`P=10log((I)/(I_o))`

Here,

`I_o=10^(-12)`

Thus,

`\begin{gathered} P=10log((0.00458)/(10^(-12))) \\ \Rightarrow P=96.6\text{ dB} \end{gathered}`

Conclusion

The relative intensity is 96.6 dB