The given equation is expressed as
4(3a + 5) = 2(6a + 10)
The first step is to open the brackets on both sides of the equation by multiplying the terms inside the brackets by the term outside. It becomes
4 * 3a + 4 * 5 = 2 * 6a + 2 * 10
12a + 20 = 12a + 20
Collecting like terms, it becomes
12a - 12a = 20 - 20
0 = 0
It has an infinite number of solutions