Register
How many grams of ko2 are needed to form 8.5 g of o2?
110k views
4 votes
How many grams of ko2 are needed to form 8.5 g of o2?

User Pdsafs Df Apk
by
6.6k points

1 Answer

4 votes
Assuming molar mass of O2 = 32 gm/mole required moles of O2 = 8.5/32 = 0.266 moles requied moles of KO2= (4/3)*0.266 = 0.354 moles Molecular weight of KO2 = 39+32 = 71 gm/mole Weight = 71*0.354 = 25.134 gms
User Cejast
by
6.3k points
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

7.2m questions

9.6m answers

Other Questions

How do you balance __H2SO4 + __B(OH)3 --> __B2(SO4)3 + __H2O
As an object’s temperature increases, the ____________________ at which it radiates energy increases.
Key facts of covalent bonding
Three chemistry students measured the length of a copper bar. The recorded lengths were 5.05 cm, 5 cm , and 5.1 cm, What is the average length of the bar by showing my work ?
How many protons, electrons, and neutrons are in I- and Li+ ?
Link Copied!