The most likely dimensions for the pirate's plank are length (l) of 7 feet and width (w) of 2 feet, satisfying both the perimeter and area conditions.
The correct answer is option C.
To find the length and width of the pirate's plank, let's denote the length as "l" and the width as "w". The perimeter (P) is given by P = 2l + 2w, and the area (A) is given by lw. Given that the perimeter is 18 feet and the area is 14 square feet, we can set up a system of equations:
Equation 1: 2l + 2w = 18 (perimeter)
Equation 2: lw = 14 (area)
Let's analyze the answer choices:
A. l = 6 ft, w = 3 ft
B. l = 14 ft, w = 1 ft
C. l = 7 ft, w = 2 ft
D. l = 9 ft, w = 2 ft
Substitute these values into the equations to check for consistency:
For Option A: 2(6) + 2(3) = 12 + 6 = 18 (perimeter checks) and 6 times 3 = 18 (area doesn't match 14).
For Option B: 2(14) + 2(1) = 28 + 2 = 30 (perimeter doesn't match 18).
For Option C: 2(7) + 2(2) = 14 + 4 = 18 (perimeter checks) and 7 times 2 = 14 (area checks).
For Option D: 2(9) + 2(2) = 18 + 4 = 22 (perimeter doesn't match 18).
Therefore, the most likely answer describing the length and width of the pirate's plank is Option C: l = 7 ft and w = 2 ft.
The question probable may be:
The pirate's plank has a perimeter of 18 feet and an area of 14 square feet. Which answer below most likely describes the length and width of the pirate's plank? A. ( l = 6 ft. w = 3 ft. B.l = 14 ft w = 1 ft. C.I = 7 ft. w = 2 ft. D.l = 9 ft. w = 2 ft.