Question

Write the perimeter of the triangle as a simplified expression y+64y-22yt1

Answer 1

Given the triangle;

The perimeter of a shape is the sum of the sides or outer parts of the shape.

Thus, the perimeter of the triangle is;

`y+6+4y-2+2y+1`

Then, we simplify further by collect like terms, we have;

`\begin{gathered} y+4y+2y+6-2+1 \\ =7y+5 \end{gathered}`