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A truck accelerating at 0.0083 meters/secondÆ covers a distance of 5.8 × 10Ê meters. If the truck's mass is 7,000 kilograms, what is the work done to reach this distance?…
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A truck accelerating at 0.0083 meters/secondÆ covers a distance of 5.8 × 10Ê meters. If the truck's mass is 7,000 kilograms, what is the work done to reach this distance?…
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Jan 2, 2018
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A truck accelerating at 0.0083 meters/secondÆ covers a distance of 5.8 × 10Ê meters. If the truck's mass is 7,000 kilograms, what is the work done to reach this distance?
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Andrew Scott Evans
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Answer:
58.1*(5.8*10^4) =3,369,800 Joules. hope it helps
Fantabolous
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Jan 3, 2018
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work done = force * distance moved (in direction of the force)
force= mass* acceleration
force=58.1N
58.1*(5.8*10^4)
=3,369,800 J
Biggdman
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Jan 7, 2018
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