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A truck accelerating at 0.0083 meters/secondÆ covers a distance of 5.8 × 10Ê meters. If the truck's mass is 7,000 kilograms, what is the work done to reach this distance?
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A truck accelerating at 0.0083 meters/secondÆ covers a distance of 5.8 × 10Ê meters. If the truck's mass is 7,000 kilograms, what is the work done to reach this distance?

User Andrew Scott Evans
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2 Answers

4 votes

Answer:

58.1*(5.8*10^4) =3,369,800 Joules. hope it helps

User Fantabolous
by
8.5k points
4 votes

work done = force * distance moved (in direction of the force)

force= mass* acceleration

force=58.1N

58.1*(5.8*10^4)
=3,369,800 J
User Biggdman
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