Question

Silver nitrate, agno3, reacts with iron(iii) chloride, fecl3, to give silver chloride, agcl, and iron(iii) nitrate, fe(no3)3. a solution containing 18.00 g of agno3 was mixed with a solution containing 32.40 g of fecl3. how many excess grams of the excess reactant remain after the reaction is over?

Answer 1

To determine the excess reactant after a reaction between silver nitrate and iron(III) chloride, calculate the moles of each reactant, identify the limiting reactant, and then calculate the remaining mass of the excess reactant using stoichiometry.

Step-by-step explanation:

The subject of the question is stoichiometry, which is a section of chemistry that involves the calculation of the quantities of reactants and products in chemical reactions. Specifically, the question asks to determine the excess grams of reactant remaining after a reaction between silver nitrate (AgNO3) and iron(III) chloride (FeCl3) has taken place.

To find the answer, we would calculate the moles of both reactants using their given masses and molar masses. Then, using the balanced chemical equation, we could determine the limiting reactant and the amount of excess reactant. From there, we can calculate the mass of the excess reactant remaining.

Answer 2

3 AgNO3 + FeCl3 = Fe(NO3)3 + 3 AgCl moles AgNO3 = 18.0 g/ 169.87 g/mol=0.106 moles FeCl3 required = 0.106/3=0.0353 mass FeCl3 = 162.206 g/mol x 0.353 mol=5.73 g mass FeCl3 in excess = 32.4 - 5.73 =26.7 g. 26.7 gram of excess reactant remain after the reaction is over