Question

About how many units apart are point S and point Q

Answer 1

The point S is at (-2,-8)

The point Q is at (8,7)

Distance formula is express as:

`\text{ Distance=}\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2_{^{}}}`

The coordinates are:

`\begin{gathered} (x_1,y_1)=(-2,-8) \\ (x_2,y_2)=(8,7) \end{gathered}`

SUbstitute the value and simplify for the distance

`\begin{gathered} \text{ Distance=}\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2_{^{}}} \\ \text{Distance}=\sqrt[]{(8-(-2)^2+(7-(-8))^2} \\ \text{Distance}=\sqrt[]{(8+2)^2+(7+8)^2}_{} \\ \text{Distance}=\sqrt[]{10^2+15^2} \\ \text{Distance}=\sqrt[]{100+225} \\ \text{Distance}=\sqrt[]{325} \\ \text{Distance}=18.02\text{ unit} \end{gathered}`

The point S and Q are 18.02 unit away